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1. Two times Mark's age is 8 more than six times his son's age. Ten years ago, the sum of their ages was 44. The age of the son is:
A. 49
B. 15
C. 20
D. 18
2. John's age 13 years ago was 1/3 of his age 7 years hence. How old is John?
A. 15
B. 21
C. 23
D. 27
3. JM is 41 years old and in seven years, he will be four times as old as his son is at that time. How old is his son now?
A. 9
B. 4
C. 5
D. 8
4. Revned is three times as old as his son. Four years ago, he was four times as old as his son was at that time. How old is his son?
A. 36
B. 24
C. 32
D. 12
5. The ages of Maria and her daughter are 45 and 5 years, respectively. How many years will Maria be three times as old as her daughter?
A. 5
B. 10
C. 19
D. 20
6. Mary Ann is 24 years old. Mary Ann is twice as old as Verna was when Mary Ann was as old as Verna is now. How old is Verna?
A. 16
B. 18
C. 15
D. 20
7. The sum of Michael and Edesa's ages is twice the sum of their children's ages. Five years ago, the sum of their ages is four times the sum of their children's ages. In fifteen years, the sum of their ages will be equal to the sum of their children's ages. How many children were in the family?
A. 2
B. 3
C. 4
D. 5
8. Bobadilla is 5 yrs. older than Bobin. In 5 yrs., the product of their ages is 1.5 times the product of their present ages. How old is Bobin now?
A. 18
B. 20
C. 27
D. 25
9. Kevin is 41 yrs. old and his son Gabriel is 9. In how many years will Kevin be three times as old as Gabriel?
A. 7
B. 8
C. 9
D. 10
10. Ianne is twice as old as Paul and Ronnel is twice as old as Ianne. In ten years, their combined ages will be 58. How old is Ianne now?
A. 8
B. 4
C. 6
D. 10
Solutions to these problems will be posted on April 12, 2012. Another set of problems will be updated on the same date.
GOD BLESS!!!
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